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Tuesday 26 October 2010 4:43:51 am
Hi viraj, you may set a submenu class through an if condition according to its parent node id. You should already have your list of fetched items..
{def $submenu_items = fetch( 'content', 'list', hash( 'parent_node_id', $root_node.node_id, ...}then inside the foreach loop...
{foreach $submenu_items as $key => $item}....declare and set the item class according to its parent node id..
..
{def $item_class=""}
{if $item.parent_node_id|eq([here goes the actual parent node id])}
{set $item_class = "[here goes your style-class-name]")}
{/if}
{if $item.parent_node_id|eq([here goes the other parent node id])}
{set $item_class = "[here goes the other style-class-name]")}
{/if}
{if $item.parent_node_id|eq([again like above])}
[..and so on depending on the main menu items you have]
{/if}and then include the class in the item tag..
<a .. class={$item_class}>{$item.name}</a>and of course set the classes in your css file
.class-name1 {color: #red;}
.class-name2 {color: #green;}
loredanaebook.it
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