Date datatype formating

Wednesday 21 May 2003 5:18:50 am

Hi ... (agian) :)

listen, you have add to your class date datatype, to make the user insert the date ,am i right ?

if yes, then you cann`t format the date, coz is insert it to the databese with another format (2002.12.20), for formating the date as you need, the date must be timestamp, it`s look like this (15689186), it`s the number of secends, if u count lets say 6 month is 7776000 secend as i think, so in ur case u need to reformat it and then send it back to datatime operator, u will need to write some php code for that, the function for converting ur date is easy:

Function DateToTimonthtamp($date)
{
$date=str_replace('.','',$date);

$year = substr( $date, 0, 4 ) ;
$month = substr( $date, 4, 2 ) ;
$day = substr( $date, 6, 2 ) ;
$hours = substr( $date, 8, 2 ) ;

$unixTime = strtotime( "$year-$month-$day" ) ;
return $unixTime ;
}
echo DateToTimonthtamp("2002.12.20");

but how to use it in ez32 code is hard !

what ever, ur date look nice, keep it at is it :)

Friday 23 May 2003 6:53:44 pm

Hi Mario

Try
{$content_version.data_map.published.data_int|datetime(custom,"%d %m %Y")}

{attribute_view_gui attribute=$content_version.data_map.published|datetime(custom,"%d %m %Y")}

doesn't work as the attribute_view_gui returns the formated datetime and the datetime function expects an interger as a parameter.

Cheers
Bruce

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