how to access the "email" value of the ezusert type

Thursday 17 February 2005 3:39:15 am

Hello

Here is my (quick) question.

I have a content object attribute identified by user_account of the ezuser type. I'd like to know how to access the email value of the user account in the attribute ?

here is the code I unsuccesfully tested

$dataMap = $object->dataMap();
$email = $dataMap['user_account']->attribute('email');

Any better idea ?

Olivier

Thursday 17 February 2005 5:02:27 am

Thanks it works great !

Btw how to know what is the eztype of the object attribute $user_obj obtained by

$user_obj = $dataMap[$attrib]->content();

?

I promise not to send silly question anymore ... today !

O.

Thursday 17 February 2005 6:44:17 am

Olivier,

The content() function of a contentobject attribute either returns a simple type (string, integer, boolean, float, array, ...) or an object of a "helper" class (e.g. ezuser). For simple types, you can use PHP's gettype() function. For objects, you can use PHP's get_class() function. Example:

$content = $dataMap[$attrib]->content();
$type = gettype( $content );

if( $type == 'object' )
{
  $type = get_class( $content );
}

print( $type );

You can also trace it through the PHP code if you're familiar with (sometimes) complex PHP code. That's the way Tom and I learned it.

Eivind,

$current_user is not a node object. I assume your $current_user is the result of a fetch of the currently logged in user. In that case, the result of the fetch is exactly the same than that of the content() function of a ezuser datatype.

Olivier's code:

print( get_class( $dataMap['user_account']->content ) );

and your code:

{get_class( $current_user )}

would both say the same thing: ezuser

The .email in the templates then translates to the ->attribute( 'email' ) in PHP code.

hth

Hans
http://blog.hansmelis.be