Datatype Selection and Array

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Author	Message
Leandro Alves	Monday 30 August 2004 8:49:29 am Hi! I created a new datatype selection (name: rating) with three choices: -Very good -Good -Poor So now, I would like to show these names above in my template... I tried this code in my line view: {$node.object.data_map.rating.content} But this return only the word <b>"array"</b> in my result... <b>What I can do to show "Very Good" or "Good" or "Poor" separately in my result??</b> This code didn't work too :( {$node.object.data_map.rating.0.content} {$node.object.data_map.rating[1].content} Thank's a lot! Leandro
Paul Borgermans	Monday 30 August 2004 9:09:14 am I think Hans & Tom need to upload their enhanced selection datatype in pubsvn and the contributions ;-) Look at the datatype template for viewing the selection datatype. With the numbers, you still need to do a lookup in the class definition. -paul eZ Publish, eZ Find, Solr expert consulting and training http://twitter.com/paulborgermans
Hans Melis	Monday 30 August 2004 9:16:12 am Paul is right, we should move our enhanced selection datatype to the public repository. I'll make a mental note ;-) Leandro, did you really make your own datatype or did you just put the datatype "Selection" in one of the content classes you created? If you did the latter, it should be as simple as calling {attribute_view_gui attribute=$node.object.data_map.rating}. If you did make your own datatype (which is PHP code) it all depends on how you've structured the data. In general, the .content property contains the result of the function objectAttributeContent() in the datatype. Hans http://blog.hansmelis.be
Leandro Alves	Monday 30 August 2004 10:39:34 am Thank's a lot for your reply Hans!!! I didn't make my own datatype, I just put the datatype "Selection" in one of my content class. :) The {attribute_view_gui attribute=$node.object.data_map.rating} works fine here... Thank's again Leandro