Forums / Setup & design / Show topfolders name in right column.
Valentin Svelland
Monday 14 July 2003 6:23:27 am
I have contentfolders in three levels in my site, and I want visitors to read an output in the right column of which topfolder they're currently at.
Say, the visitors reading an article under /News/Culture/Theater/, I still want the output in the column to read "News" - this being the topfolder. I used to fill in and write out the description-field of the folder, but this is no good solution. This way I can't write out the topfolders name when the visitor is displaying an article either..
Any suggestions?
Claire Lin
Thursday 17 July 2003 12:09:33 am
The attribute $node.path_array or $node.path contains the info of all the parent nodes down to the current node. For example, {$node.path[0].name} will show "Root Folder", {$node.path[1].name} will probably be "News" (if your News object is one level under Root Folder).
You can use {$node|attribute(show)} in the template, then you will see the values of $node.path_array or $node.path.
Claire
Thursday 17 July 2003 1:34:47 am
Thanks Claire! I'm sure this is the solution. As you say {$node.path[0].name} shows the root folders name, and {$node.path[1].name} my level "MySite".
However {$node.path[2].name} doesn't return "News", "Sports" and so on. No output, just a blank line. weird.. Trying to figure out why. The names exist so I can't understand why [2] doesn't return "News" as in my structure / Root Folder / MySite / News..
Ok, I found this error in debug: ----------------------------------Error: eZTemplate @
design/mysite/override/templates/pagelayout_mysite.tpl:330[24] Jul 17 2003 10:50:33 No such attribute for array(2): 3Choose one of following: 0, 1
Script start
Module start 'content'
Module end 'content'
Script end
Time used to render debug report: 0.0001 secs